Multiple choice

In this question two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option.\newline I. (p^3 + 783 = 775)\newline II. (6q^2 - 19q + 15 = 0)

  1. If p < q

  2. If p ≥ q

  3. If p ≤ q

  4. If p > q

  5. If p = q or no relation between p and q can be established
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A Correct answer
Explanation

For equation I: p³ + 783 = 775, so p³ = -8, giving p = -2. For equation II: 6q² - 19q + 15 = 0. Using the quadratic formula: q = (19 ± √(361 - 360))/12 = (19 ± 1)/12, giving q = 20/12 = 5/3 ≈ 1.67 or q = 18/12 = 3/2 = 1.5. Comparing p = -2 with q values (1.67, 1.5), we have p < q in both cases.

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