Multiple choice

In every question there are two equations you have to solve and give answer- I. (20x^2 + 31x + 12 = 0) II. (21y^2 - 23y + 6 = 0)

  1. If x < y

  2. If x > y

  3. If x ≤ y

  4. If x ≥ y

  5. If x = y or no relation between x and y can be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving 20x² + 31x + 12 = 0 gives x = -3/4 = -0.75 or x = -4/5 = -0.8. Solving 21y² - 23y + 6 = 0 gives y = 2/7 ≈ 0.286 or y = 3/7 ≈ 0.429. Both possible values of x (-0.75 and -0.8) are less than both possible values of y (0.286 and 0.429) since negative < positive. Therefore x < y is always true.

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