In covering a distance of 30 km., Abhay takes 2 hours more than Sameer. If Abhay doubles his speed ,then he would take 1 hours less than Sameer .Abhay's speed (in km/hr.) is - 30 किमी. की दूरी तय करने में अभय, समीर से 2 घंटे अधिक समय लेता हैं यदि अभय अपनी चाल को दोगुना कर दे तो वह समीर से एक घंटा कम समय लेगा। अभय की चाल (किमी/घंटा) में है-

Let Sameer's time be t hours. Abhay's time = t+2 hours. Sameer's speed = 30/t, Abhay's speed = 30/(t+2). When Abhay doubles speed: 60/(t+2) = t-1 (1 hour less than Sameer). Cross-multiplying: 60 = (t+2)(t-1) = t²+t-2. So t²+t-62=0. Solving: t = [-1±√(1+248)]/2 = [-1±√249]/2 ≈ 7.39. Abhay's speed = 30/(9.39) ≈ 3.2, which doesn't match. Let me redo: if Abhay takes 2 hours more, and doubling makes him take 1 hour less, then original: t+2, new: 2×30/(t+2) = 30/(t-1). Solving gives t=6, Abhay's speed = 30/8=3.75, still not matching options. The correct approach: let Abhay's speed = v, then 30/v = 30/s + 2 and 30/(2v) = 30/s - 1. This gives v=5 km/h.