In a circle with centre O, an arc ABC subtends an angle of 132o at the centre of the circle. Chord AB is produced to point P. Then ∠CBP is equal to :

In a circle, an exterior angle formed by extending a chord equals half the difference of 360° and the central angle subtended by the intercepted arc. The arc ABC subtends 132° at center O, so the remaining arc AC measures 360° - 132° = 228°. The exterior angle ∠CBP equals half of this remaining arc: 228°/2 = 114°. However, ∠CBP is the angle formed outside the circle, which is supplementary to the angle in the alternate segment. Using the exterior angle property for chords: ∠CBP = (360° - 132°)/2 = 66°. Alternatively, ∠CBP equals the angle in the opposite segment, which is half the central angle subtended by the same arc: 132°/2 = 66°.