Multiple choice

In the following questions two equations I and II are given. You have to solve both the equations and give answer.(I. x^2 – 32x + 255 = 0 )(II. y^2 – 26y + 168 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relationship cannot be determined
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A Correct answer
Explanation

Solving x² - 32x + 255 = 0 gives x = 17, 15. Solving y² - 26y + 168 = 0 gives y = 14, 12. Since both x values (17 and 15) are greater than both y values (14 and 12), x > y is true.

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