Multiple choice

In each of the following questions, two equations I and II are given. You have to solve them and-(I) \quad p^2 – p – 2 = 0 (II) \quad q^2 + 3q + 2 = 0\Give answer-

  1. If p > q

  2. If p ≥ q

  3. If p < q

  4. If p ≤ q

  5. If p = q or relationship can not be established
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solve equation I: p² - p - 2 = 0. Factor: (p - 2)(p + 1) = 0, so p = 2 or p = -1. Solve equation II: q² + 3q + 2 = 0. Factor: (q + 1)(q + 2) = 0, so q = -1 or q = -2. Compare all possible values: When p = 2 and q = -1, then p > q. When p = 2 and q = -2, then p > q. When p = -1 and q = -1, then p = q. When p = -1 and q = -2, then p > q. In all cases, p is either greater than or equal to q, so p ≥ q is always true. Therefore, the answer is B.

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