Multiple choice

In the following questions two equations I and II are given. Solve both the equations and give answer $( (I) \quad 2x + 3y = 11 )$ $( (II) \quad 4x + 5y = 19 )$

  1. $\( x > y \)$
  2. $\( x \ge y \)$
  3. $\( x < y \)$
  4. $\( x \le y \)$

  5. x = y or relation can not be established.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving the system: Multiply (I) by 2: 4x+6y=22. Subtract from (II): (4x+5y)-(4x+6y)=19-22 gives -y=-3, so y=3. Substituting in (I): 2x+9=11 gives 2x=2, x=1. Since x=1 < y=3, option C is correct.

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