Multiple choice

In each of these questions two equations I and II are given. You have to solve both the equations and give answer. I. (3x^{2} - 19x = 14) II. (2y^{2} + 5y - 3 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or no relation can be established between x and y.
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Equation I: 3x² - 19x - 14 = 0 factors to (3x + 2)(x - 7) = 0, so x = 7 or x = -2/3. Equation II: 2y² + 5y - 3 = 0 factors to (2y - 1)(y + 3) = 0, so y = 1/2 or y = -3. Comparing values: x = 7 > y = -3, x = 7 > y = 1/2, x = -2/3 < y = 1/2, x = -2/3 > y = -3. No consistent relation exists.

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