Multiple choice

In how many different ways can the letters of the word "DARYABAD" be arranged?

  1. 3360

  2. 3260

  3. 3160

  4. 3350

  5. 3060
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

DARYABAD has 8 letters with A repeated twice and D repeated twice. Arrangements = 8! / (2! × 2!) = 40320 / 4 = 10080. Wait, let me recalculate: 8! = 40320, divided by 4 = 10080. Hmm, this doesn't match option A (3360). Let me check the word again: D-A-R-Y-A-B-A-D - that's 8 letters with A appearing 3 times and D appearing 2 times. So 8! / (3! × 2!) = 40320 / 12 = 3360.

Keep practicing — related questions