$( \text{In each of the following question, two equation (I) and (II) is given. You have to solve them and answer the question.} )$ $( (I) 2x^2 + 11x - 63 = 0 )( \qquad (II) y^2 - 2y - 63 = 0 )$

Solve equation (I): 2x² + 11x - 63 = 0 factors to (2x - 7)(x + 9) = 0. So x = 7/2 = 3.5 or x = -9. Solve equation (II): y² - 2y - 63 = 0 factors to (y - 9)(y + 7) = 0. So y = 9 or y = -7. Comparing all combinations: when x = 3.5, y could be 9 (x < y) or -7 (x > y). When x = -9, y could be 9 (x < y) or -7 (x < y). Since the relationship varies (sometimes x < y, sometimes x > y), it cannot be established, confirming option E.