Multiple choice

$In each of the following questions, (I) and (II) equations are given. You have to solve them and \ I. (x^2 + 2x + 1 = 0)\ II. (y^2 = 4)$ Give answer-

  1. If x>y

  2. If x≥y

  3. If x<y

  4. If x≤y

  5. If x=y or relationship can not be determined
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

x² + 2x + 1 = 0 is (x+1)² = 0, giving x = -1 (repeated root). y² = 4 gives y = 2 or y = -2. When y = 2, we have x < y since -1 < 2. When y = -2, we have x > y since -1 > -2. Since the relationship changes depending on which value of y we choose, it cannot be determined.

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