Multiple choice

In each of the following questions, (I) and (II) equations are given. You have to solve them and Give answer. $I. (x^2 + 5x + 6 = 0)$ $II. (y^2 + 7y + 12 = 0)$ Give answer-

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship can not be determined
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solving x² + 5x + 6 = 0 gives (x+2)(x+3) = 0, so x = -2 or x = -3. Solving y² + 7y + 12 = 0 gives (y+3)(y+4) = 0, so y = -3 or y = -4. For all possible combinations: (-2,-3): -2 ≥ -3; (-2,-4): -2 ≥ -4; (-3,-3): -3 ≥ -3; (-3,-4): -3 ≥ -4. Every combination satisfies x ≥ y.

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