Multiple choice

(\text{In each of the following question, two equation (I) and (II) is given. You have to solve them and answer the question})\n(\text{(I) } 8x^2 + 3x = 38 \text{ (II) } 6y^2 + 34 = 29y)

  1. If x > y

  2. If x < y

  3. If x ≤ y

  4. If x ≥ y

  5. If x = y or Relationship cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solve equation (I): 8x² + 3x - 38 = 0 factors to (8x - 19)(x + 2) = 0, giving x = 19/8 = 2.375 or x = -2. Solve equation (II): 6y² - 29y + 34 = 0 factors to (2y - 17)(3y - 2) = 0, giving y = 17/2 = 8.5 or y = 2/3. Taking positive values: x = 2.375, y = 8.5, so x < y. Since x < y is true, x ≤ y is also true.

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