Multiple choice

From a bag which contains 4 black balls, 3 green balls and 5 yellow balls, what is the probability of selecting 3 balls of different colors?

  1. 6/11

  2. 3/11

  3. 1/2

  4. 4/11
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Total balls = 4+3+5 = 12. To get 3 balls of different colors (1 black, 1 green, 1 yellow), calculate: (4/12)×(3/11)×(5/10) = 60/1320 = 1/22. Since the 3 colors can be arranged in 3! = 6 ways, total probability = 6 × (1/22) = 6/22 = 3/11. This considers all possible orders of drawing one ball of each color.

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