A,B and C are three points on a circle such that the angles subtended by the chord AB and AC at the centre 0 are 〖110〗^∘ and 〖130〗^∘, respectively. Then the value of ∠BAC is:

For points on a circle, the angle at the center is twice the angle at the circumference subtended by the same chord. Central angle AOB = 110° and AOC = 130°, so angle BOC = 360° - 110° - 130° = 120° (assuming points are arranged around the circle). Since angle BAC subtends chord BC at the circumference, it equals half of angle BOC: 120° / 2 = 60°.