Multiple choice

In the following questions two equation (I) and (II) are given. You have to solve both the equation and give answer. I. (x^2 + 6 = 5x) II. (y^2 + 13y = -42)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving equation I: x² - 5x + 6 = 0 factors to (x-2)(x-3) = 0, so x = 2 or 3. Solving equation II: y² + 13y + 42 = 0 factors to (y+6)(y+7) = 0, so y = -6 or -7. All positive values of x (2, 3) are greater than all negative values of y (-6, -7). Therefore x > y, making option A correct.

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