Multiple choice

In the following questions two equation (I) and (II) are given. You have to solve both the equation and give answer. $I. (x^2 + 9x + 20 = 0) II. (y^2 + 16y + 63 = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established.
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving equation I: x² + 9x + 20 = 0 factors to (x+5)(x+4) = 0, so x = -5 or -4. Solving equation II: y² + 16y + 63 = 0 factors to (y+9)(y+7) = 0, so y = -9 or -7. For all combinations: when x=-5, x > y (since -5 > -7, -5 > -9); when x=-4, x > y (since -4 > -7, -4 > -9). Therefore x > y always, confirming option A.

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