Multiple choice

In the following questions two equation (I) and (II) are given. You have to solve both the equation and give answer. $I. (x^2 - 14x + 48 = 0) II. (y^2 + 7y + 12 = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving equation I: x² - 14x + 48 = 0 factors to (x-8)(x-6) = 0, so x = 8 or 6. Solving equation II: y² + 7y + 12 = 0 factors to (y+4)(y+3) = 0, so y = -4 or -3. All values of x (8, 6) are greater than all values of y (-4, -3). Therefore x > y is always true, making option A correct.

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