(\text{Solve the following equations and compare the values of x and y:}\ \text{(I) } x^2 - 7x + 12 = 0 \ \text{(II) } y^2 - 12y + 32 = 0)

Equation I: x² - 7x + 12 = 0 factors as (x - 3)(x - 4) = 0, so x = 3 or x = 4. Equation II: y² - 12y + 32 = 0 factors as (y - 4)(y - 8) = 0, so y = 4 or y = 8. Comparing: When x = 3, y can be 4 or 8 (x < y in both cases). When x = 4, y can be 4 (x = y) or 8 (x < y). In all cases, x ≤ y is true. x is never greater than y.