Multiple choice

In each of the following questions, two equations (I) and (II) are given. You have to solve them and answer the questions. $I. (9x^2 - 45x + 56 = 0)$ $II. (4y^2 - 7y - 2 = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
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A Correct answer
Explanation

For equation I: 9x² - 45x + 56 = 0 factors to (3x - 8)(3x - 7) = 0, giving x = 8/3 or x = 7/3. For equation II: 4y² - 7y - 2 = 0 factors to (4y + 1)(y - 2) = 0, giving y = 2 or y = -1/4. Comparing both roots of x (2.67 and 2.33) with both roots of y, both x values are greater than both y values, so x > y.

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