Multiple choice

In each of the following questions, two equations are given. You have to solve them and answer the question. ( (I) ) ( 6x^2 + 31x + 35 = 0 ) ( (II) ) ( 2y^2 + 3y + 1 = 0 )

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Equation (I): 6x² + 31x + 35 = 0 factors as (2x+5)(3x+7) = 0, giving x = -5/2 or -7/3. Equation (II): 2y² + 3y + 1 = 0 factors as (2y+1)(y+1) = 0, giving y = -1/2 or -1. Numerically: x ∈ {-2.5, -2.33} and y ∈ {-0.5, -1}. Both x values are less than both y values, so x < y.

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