Multiple choice

In each of the following questions two equations I and II are given. You have to solve the equations and then answer. $I. (x^2 - 14x + 48 = 0) II. (y^2 + 6 = 5y)$

  1. If x < y

  2. If x ≤ y

  3. If x > y

  4. If x ≥ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solve I: x^2 - 14x + 48 = 0. This factors as (x-6)(x-8) = 0, so x = 6 or x = 8. Solve II: y^2 + 6 = 5y, rearranging gives y^2 - 5y + 6 = 0, which factors as (y-2)(y-3) = 0, so y = 2 or y = 3. Comparing all values: x can be 6 or 8, y can be 2 or 3. In all cases, x > y (6>2, 6>3, 8>2, 8>3). Therefore option C is correct.

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