Two cars started from point A and B towards B and A respectively. They crosses each other in one hour and the first car reaches A, 5/6 hour before the second car reaches B. If the distance between A and B is 50 Km. What is the speed of the slower car?(in km/hr)

Let speeds be s1 and s2. They meet in 1 hour, so combined speed = 50 km/h, thus s1+s2=50. Crossing point is at distance s1 from A. First car travels remaining distance s2 at speed s1. Time = s2/s1. Second car travels s1 at speed s2, time = s1/s2. Difference = 5/6: s2/s1 - s1/s2 = 5/6. Solving gives s1=20, s2=30. Slower car = 20 km/h.