Multiple choice

In a box there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

  1. $\(\frac{2}{3}\)$
  2. $\(\frac{1}{4}\)$
  3. $\(\frac{1}{6}\)$
  4. $\(\frac{1}{3}\)$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Total balls = 8 red + 7 blue + 6 green = 21 balls. 'Neither red nor green' means we want only blue balls. There are 7 blue balls. Probability = 7/21 = 1/3. Option D is correct.

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