Multiple choice

In each of the following questions, two equations are given. You have to solve them and answer $( (I) \space x^{2} + 9x + 14 = 0 \space\space\space\space\space\space (II) \space y^{2} + y -2 = 0 )$

  1. $\( x > y \)$
  2. $\( x \ge y \)$
  3. $\( x < y \)$
  4. $\( x \le y \)$

  5. x = y or relationship can not be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solving equation (I): x² + 9x + 14 = 0 factors as (x + 7)(x + 2) = 0, giving x = -7 or x = -2. Solving equation (II): y² + y - 2 = 0 factors as (y + 2)(y - 1) = 0, giving y = -2 or y = 1. Comparing values: when x = -7, x < both y values (-7 < -2 and -7 < 1). When x = -2, x equals y = -2 and x < y = 1. Therefore x ≤ y is always true (x can equal y when both are -2, or x is less than y in all other cases).

Keep practicing — related questions