Multiple choice

In each of the following questions, two equations are given. You have to solve them and (I) (2x^2 - 21x + 55 = 0) (II) (5y^2 - 17y + 14 = 0)

  1. If x>y

  2. If x≥y

  3. If x<y

  4. If x≤y

  5. If x=y or relationship can not be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

For 2x² - 21x + 55 = 0: using quadratic formula, x = (21 ± 1)/4, so x = 5 or 5.5. For 5y² - 17y + 14 = 0: y = (17 ± 3)/10, so y = 1.4 or 2. In all four combinations, x values (5, 5.5) are always greater than y values (1.4, 2). Therefore x > y is consistently true, making option A correct.

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