Multiple choice

In each of the following questions, two equations are given. You have to solve them and give answers- (I) (P^2 + 4 = -4P) ()\n(II) (Q^2 + 7Q + 12 = 0)

  1. If P < Q

  2. If P ≤ Q

  3. If P > Q

  4. If P ≥ Q

  5. If P = Q or relationship cannot be established.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For equation I: P^2 + 4 = -4P gives P^2 + 4P + 4 = 0, so (P+2)^2 = 0, hence P = -2. For equation II: Q^2 + 7Q + 12 = 0 factors to (Q+3)(Q+4) = 0, so Q = -3 or Q = -4. Since P = -2 and Q = -3 or -4, we have P > Q.

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