Multiple choice

In the following questions two equation I and II are given you have to solve both the equation and give answer- I. (x^{2}–7x+12=0) II. (y^{2}–12y+32=0)

  1. If x>y

  2. If x≥y

  3. If x<y

  4. If x≤y

  5. If x=y or the relationship can not be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solve equation I: x²-7x+12=0 factors to (x-3)(x-4)=0, so x=3 or x=4. Solve equation II: y²-12y+32=0 factors to (y-4)(y-8)=0, so y=4 or y=8. Comparing values: x can be 3 or 4, while y can be 4 or 8. In all cases x≤y (when x=3: 3≤4, 3≤8; when x=4: 4≤4, 4≤8). Therefore option D (x≤y) is correct.

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