Multiple choice

A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work in 44 days. In how many days shall B finish the work alone?

  1. 30

  2. 40

  3. 60

  4. 70

  5. 45
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let A's 1 day work = 1/a, B's 1 day work = 1/b. Given 1/a + 1/b = 1/30. A worked 16 days, so work done = 16/a. Remaining = 1 - 16/a, done by B in 44 days: (1 - 16/a) = 44/b. Substituting b from first eq: b = 30a/(a-30). After solving: a = 60, b = 60. Therefore B alone takes 60 days.

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