Multiple choice

A chord 21 cm long is drawn in a circle of diameter 25 cm. The perpendicular distance of the chord from the centre is:

  1. $\(\sqrt{41}\)$
  2. $\(\sqrt{46}\)$
  3. $\(\sqrt{51}\)$
  4. $\(\sqrt{47}\)$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For a chord of length 21 cm in a circle with diameter 25 cm (radius 12.5 cm), the perpendicular distance from center = √(r² - (L/2)²) = √(12.5² - 10.5²) = √(156.25 - 110.25) = √46 cm. This formula comes from the right triangle formed by the radius, half-chord, and perpendicular distance. Option B is correct.

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