Multiple choice

In the following question two equation numbered I and II are given .You have to solve both the equations and give answer if - I. (x^2 + 17x + 72 = 0) II. (y^2 + 12y + 32 = 0)

  1. x > y

  2. x ≥ y

  3. x < y

  4. x ≤ y

  5. x = y or the relationship cannot be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Equation I: x²+17x+72=(x+8)(x+9) gives x=-8,-9. Equation II: y²+12y+32=(y+4)(y+8) gives y=-4,-8. x values are -8,-9. When x=-8, y can be -8 (equal) or -4 (greater). When x=-9, it's less than both y values. So x≤y holds.

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