Arun got married 10 year ago, his present age is (\frac{4}{3}) times the age at his marriage, arun's brother is 4 years younger to Arun .Find the age of Arun's brother at the time of Arun marriage ?

Let Arun's age at marriage be x. His present age (10 years later) is 4/3 times that age, so x + 10 = 4x/3. Solving: 3x + 30 = 4x, thus x = 30. Arun's present age is 40. His brother is 4 years younger, so brother's present age is 36. At Arun's marriage (10 years ago), the brother was 36 - 10 = 26 years old. Option B is correct.