Multiple choice

In the following questions two equations (I) and (II) are given. You have to solve both the equation and give answer- (I) ( x^{2} -1 = 0 ) (II) ( y^{2} - 12y +32 = 0 )

  1. If x > y

  2. If x < y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or the relationship can not be established.
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solving equation (I): x² - 1 = 0 gives x = ±1. Solving equation (II): y² - 12y + 32 = 0. Using quadratic formula: y = (12 ± √(144-128))/2 = (12 ± √16)/2 = (12 ± 4)/2, so y = 8 or y = 4. For all values of x (±1) and y (4, 8), we have x < y. Therefore x < y is always true. Option B is correct.

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