Multiple choice

In the following questions two equations (I) and (II) are given. You have to solve both the equations and give answer.( (I) \quad 2x^2 - 9x + 10 = 0 \quad (II) \quad 2y^2 - 13y + 20 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solving equation (I): 2x² - 9x + 10 = 0 gives x = 2 or x = 5/2. Solving equation (II): 2y² - 13y + 20 = 0 gives y = 5/2 or y = 4. For x = 2, both y values (2.5, 4) are greater. For x = 2.5, y can be 2.5 (equal) or 4 (greater). Thus, x is always less than or equal to y.

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