Multiple choice

In the following questions two equations (I) and (II) are given. You have to solve both the equations and give answer. ( (I) \quad 2x^2 + 27 + 15x = 0 \quad (II) \quad 3y^2 + 14 = 13y )

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving equation (I): 2x² + 15x + 27 = 0. Discriminant = 225 - 216 = 9, so x = (-15 ± 3)/4, giving x = -3 or x = -4.5. Solving equation (II): 3y² - 13y + 14 = 0 gives y = 2 or y = 7/3. All x values (-3, -4.5) are less than all y values (2, 2.33), so x < y.

Keep practicing — related questions