Multiple choice

In the following questions two equations numbered I and II are given. You have to solve both the equations and- $I. (3x^2 + 7x + 2 = 0)$ $II. (y^2 = 4)$ Give answer

  1. If x < y

  2. If x > y

  3. If x ≤ y

  4. If x ≥ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solve equation I: 3x² + 7x + 2 = 0 gives x = -1/3 or x = -2. Solve equation II: y² = 4 gives y = ±2. When x = -1/3, compare with y = 2 (x < y) and y = -2 (x > y). When x = -2, compare with y = 2 (x < y) and y = -2 (x = y). Since x can be less than, greater than, or equal to y depending on which values we consider, no single relationship holds consistently.

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