Multiple choice

In the following question two equations are given. You have to solve both the equations and find out the values of x and y and Give answer - ( (I) (x + 2)^{2} – 25 = 0 ) ( (II) 3y^{2} + y - 4 = 0 )

  1. x<y

  2. x>y

  3. x≤y

  4. x≥y

  5. x=y or the relationship cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solve equation (I): (x+2)²-25=0 gives x = 3 or -7. Solve equation (II): 3y²+y-4=0 factors to (y-1)(3y+4)=0, giving y = 1 or -4/3. When x = 3, x > y for both values. When x = -7, x < y for both values. Since the relationship changes based on which roots are compared, it cannot be established. Option E is correct.

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