In the following question two equations are given. You have to solve both the equations and find out the values of x and y and Give answer - ( (I) 4x^2 – 7x + 3 = 0 )( (II) y^2 – 2y + 1 = 0 )

Equation (I): 4x² - 7x + 3 = 0. Factorizing: (4x-3)(x-1) = 0, so x = 3/4 or x = 1. Equation (II): y² - 2y + 1 = 0. This is (y-1)² = 0, so y = 1. Comparing: when x = 1, x = y. When x = 3/4, x < y. Since one possible x value is less than y and the other equals y, the relationship that covers all cases is x ≤ y, which is option C. Note that x can be equal to y (when both are 1), so x < y alone is incorrect.