Multiple choice

If a man drives at (\frac{4}{5})th of his usual speed then he reaches 15 minutes late. Find his usual time taken to cover the same distance?

  1. 0.5 hour

  2. 1 hour

  3. 2 hour

  4. 2.5 hour

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Distance is constant. At (4/5) of usual speed, time becomes (5/4) of usual time. Let usual time be t hours. New time = 1.25t. Delay = 0.25t = 15 minutes = 0.25 hours. So t = 1 hour.

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