Multiple choice

Mr. Kumar drives to work at an average speed of 48 km. per hr.The time taken to cover the first 60% of the distance is 10 min more than the time taken to cover the remaining distance.How far is his office? श्री.कुमार अपने कार्य पर 48 किमी./घं की औसत चाल से गाड़ी चलाकर जाते है। पहली 60% दूरी तय करने में शेष दूरी को तय करने में लगने वाले समय की अपेक्षा 10 मिनट ज्यादा लगते है। उनका कार्यस्थल कितनी दूरी पर है?

  1. 30 km

  2. 40 km

  3. 45 km

  4. 48 km
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B Correct answer
Explanation

Let total distance = D km. First 60% = 0.6D km at 48 km/hr takes 0.6D/48 hours. Remaining 40% = 0.4D km takes 0.4D/48 hours. Difference = 10 minutes = 10/60 = 1/6 hours. So: 0.6D/48 - 0.4D/48 = 1/6. This gives 0.2D/48 = 1/6, so D = 48/1.2 = 40 km. First 24 km takes 30 min, last 16 km takes 20 min - difference is 10 min.

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