Multiple choice

(\text{In each of the following questions two equations are given. You have to solve them and give answer -})\n(\text{(I)}) (2a^2 + 20a + 50 = 0)\n(\text{(II)}) (b^2 = 25)

  1. $\(a < b\)$
  2. $\(a > b\)$
  3. $\(a \le b\)$
  4. $\(a \ge b\)$

  5. If a=b or Relationship cannot be determine
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving 2a² + 20a + 50 = 0, divide by 2: a² + 10a + 25 = 0, giving (a+5)² = 0, so a = -5 (repeated root). Solving b² = 25 gives b = 5 or b = -5. Comparing all combinations: -5 ≤ -5 (equal), -5 ≤ 5. Thus a ≤ b always holds.

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