In each of the following questions, two equations (I) and (II) are given. You have to solve them and(\text{(I)} \quad x^2+41x+418=0\\text{(II)} \quad y^2+36y+323=0

Solve x² + 41x + 418 = 0: factors to (x+19)(x+22) = 0, so x = -19 or x = -22. Solve y² + 36y + 323 = 0: factors to (y+17)(y+19) = 0, so y = -17 or y = -19. Comparing all values: x ranges from -22 to -19, y ranges from -19 to -17. Both values can equal -19, but x's maximum (-19) equals y's minimum (-19), and x can be less than y (when x=-22, y=-17). Therefore x ≤ y is correct.