Multiple choice

In each of the following questions, two equations are given. You have to solve them and $I. (x^{2} - 5 = 0) II. (4y^{2} - 24y + 35 = 0)$

  1. If x<y

  2. If x≤y

  3. If x=y or relationship can not be established

  4. If x>y

  5. If x≥y
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A Correct answer
Explanation

Solve equation I: x² - 5 = 0, so x = ±√5 ≈ ±2.236. Solve equation II: 4y² - 24y + 35 = 0. Using quadratic formula: y = (24 ± √(576 - 560))/8 = (24 ± 4)/8, giving y = 28/8 = 3.5 or y = 20/8 = 2.5. Comparing: all x values (±2.236) are less than all y values (2.5, 3.5). Thus x < y.

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