A, B and C are three points on a circle such that the angles subtended by the chord AB and AC at the center O are 110o and 130o, respectively. Then the value of angle BAC is:

Central angle for arc BC = 130° - 110° = 20°. Angle BOC = 20° at center. Angle at circumference BAC subtends same arc BC, so BAC = 20°/2 = 10°. But wait - angles AOB and AOC are 110° and 130°, so angle BOC is actually |130° - 110°| = 20°, giving BAC = 10°. This doesn't match 60°. Let me reconsider: AOB = 110°, AOC = 130°. The angle BAC intercepts arc BC. Arc BC subtends 360° - 110° - 130° = 120° at center. So angle BAC = 120°/2 = 60°. Yes, C is correct.