Multiple choice

The equation whose roots are twice the roots of the equation (x^2 - 2x + 4 = 0) is-

  1. $\(x^2 - 2x + 4 = 0\)$
  2. $\(x^2 - 2x + 16 = 0\)$
  3. $\(x^2 - 4x + 8 = 0\)$
  4. $\(x^2 - 4x + 16 = 0\)$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

If roots of x² - 2x + 4 = 0 are α and β, then α + β = 2 and αβ = 4. For roots 2α and 2β: sum = 2(α + β) = 4 and product = 4(αβ) = 16. The new equation is x² - 4x + 16 = 0.

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