Multiple choice

In each of the following questions two equations are given. You have to solve them and give answer - (I) (a^2 - 14a + 48 = 0) (II) (b^2 - 23b + 132 = 0)

  1. If a < b

  2. If a > b

  3. If a ≤ b

  4. If a ≥ b

  5. If a=b or Relationship cannot be determined

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving the quadratic equations: Equation (I) a² - 14a + 48 = 0 factors to (a-6)(a-8) = 0, giving a = 6 or a = 8. Equation (II) b² - 23b + 132 = 0 factors to (b-11)(b-12) = 0, giving b = 11 or b = 12. Comparing the values: both values of a (6, 8) are less than both values of b (11, 12), so a < b is correct.