Multiple choice

In the following question two equation numbered I and II are given .You have to solve both the equations and give answer if - ( (I) x^2 -8x+15 =0 )( (II) y^2 -3y+2=0 )

  1. x≥y

  2. x<y

  3. x≤y

  4. x>y

  5. x=y or the relation cannot be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solving equation I: x^2 - 8x + 15 = 0 gives (x-3)(x-5) = 0, so x = 3 or x = 5. Solving equation II: y^2 - 3y + 2 = 0 gives (y-1)(y-2) = 0, so y = 1 or y = 2. In all cases (x=3 or 5; y=1 or 2), x is always greater than y. Therefore x > y.

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