Multiple choice

In the following question two equation numbered I and II are given .You have to solve both the equations and give answer if - ( (I) x^2 -x-20=0 ) ( (II) y^2+7y+12=0 )

  1. $x\geq y$
  2. $x<y$
  3. $x\leq y$
  4. $x>y$

  5. x=y or the relation cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving equation I: x^2 - x - 20 = 0 gives (x-5)(x+4) = 0, so x = 5 or x = -4. Solving equation II: y^2 + 7y + 12 = 0 gives (y+3)(y+4) = 0, so y = -3 or y = -4. When x = 5, x > y (both -3, -4). When x = -4, x could equal y = -4 or be less than y = -3. Since the relationship varies, it cannot be established.

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