A's age eight years ago was equal to twice of B's age two years ago. C is six years older than B. If the respective ratio between present ages of A and C is 8: 5, what is B's present age? (In years)

Let A's present age = 8x, B's present age = y, C's present age = 5x (from ratio 8:5). Given: C is 6 years older than B, so 5x = y + 6, giving y = 5x - 6. Also: A's age 8 years ago = 2 × (B's age 2 years ago), so 8x - 8 = 2(y - 2) = 2y - 4. Substituting y = 5x - 6: 8x - 8 = 2(5x - 6) - 4 = 10x - 12 - 4 = 10x - 16. Solving: 8x - 8 = 10x - 16 gives 2x = 8, so x = 4. Therefore B's age = 5(4) - 6 = 14 years. Option E is correct.