Father is aged three times more than his son Arun. After 8 years, father would be two and a half times of Arun’s age. After further 8 years, age of father would be how many times of Arun’s age?

Let Arun's current age = x. Father is "three times more than" son means father = x + 3x = 4x. After 8 years: 4x + 8 = 2.5(x + 8). Solving: 4x + 8 = 2.5x + 20, so 1.5x = 12, giving x = 8. Father's current age = 32. After further 8 years (total 16 years from now): Father = 48, Arun = 24. Father's age = 48/24 = 2 times Arun's age.